Comm. calc

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barbeer

Senior Member
Any ideas why a design professional would have a calc that looks like:

67251va/208x2.74=118amps

?

I have seen:

67251va/208x1.732=186.8

I will admit calculations are a weaker point of mine but I have never seen that.
 
1.73 x a very good power factor?

I would have to agree that it could be a typo. Do you know what type of transformer is/was used?




(added question)
 
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Ordinarily, the equation would look like this:

P = sqrt(3)*V*I*cos(theta)

where cos(theta) is the power factor.

In this case, if you assume that the power factor is 0.95 and work the equation with the given power and voltage, what you get is a 0.6 multiplier. In other words, instead of the above equation the designer used:

0.6*P = sqrt(3)*V*I*0.95

Looks like a load diversity factor to me. He/she figured that only 60% of the equipment would be operating at any one time.
 
drbond24 said:
Looks like a load diversity factor to me. He/she figured that only 60% of the equipment would be operating at any one time.

Would you normally even show this math on a simple set of plans that electricians and inspectors(non-engineer types:smile: ) would be using in the field?
 
barbeer said:
67251va/208x2.74=118amps
67251va/208x1.732=186.8
Just an FYI...

These calculations are written improperly. They should be in either of the forms below:
VA/(V?√3) = A, or
VA/V/√3 = A​
 
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drbond24 said:
How do you get a square root symbol to show up?
Copy it from Character Map (Windows OS's). Rather than visually finding it in the "map", I use the advanced view and Search on "sq".
 
Smart $ said:
Copy it from Character Map (Windows OS's). Rather than visually finding it in the "map", I use the advanced view and Search on "sq".

There's a way to do it with just pressing keys too, but I don't remember it off hand. I think you hold down ctrl (or alt?) and press a four digit number. Anyone remember that method?
 
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