I have 100' of 1" PVC installed underground. Easiest thing to do but not the cheapest would be to finish this raceway and pull thwn into the conduit for this installation. But customer wants cheap. Other option is pull 6/3 UF into the conduit and not finish it off. I have 6/3 in hand and it will fit in 1" PVCs but I'm not sure I could pull it 100'. Maybe with lots of lube. Question is it even legal. Diameter of cable is listed as 1223 mils by 361 mils but not sure how to convert that to internal diameter of PVC. Thanks
Pie R squared (R²). Is what you need for area inch squares (in²). Then you can go to the tables in chapter 9.
Since the cable is larger in diameter on one side than the other you use the larger. 1223 mills or 1.223 inches. 1- mill = .001 inch
1223*.001= 1.223 or just move decimal three places to the left on the mill number.
Then take the diameter and turn that into radius or 1/2 the the diameter.
1.223/2= .6115r
Then we square that or take .
.6115*.6115= .37393225 this is radius squared
Take that times pie.
.337393225*3.141592= 1.74742
Since chapter 9 table used three decimals use 1.747
Now you can compare that to the number in table for 1- wire 53% fill of .441 for 1" sch 40 PVC.
As you can see not code compliant.
100% fill is .832 which is to small as well.
So for a short cut as mentioned your diameter for one inch is 1.029 in and you cable is 1.223 in
I like to use for math in field and testing for these kind of questions.
Formula, D² * .7854 much easier
The .7854 is pie /4
This way it's takes radius out of the question and mistake in math. If you forget to take D and turn into R.
Then you can size raceway.
One wire @53% with an area inch squares of 1.747 in schedule 40 PVC would be.
2.5" @ 2.488 in²
If you choose 2" @ 1.744 in² you would miss the test question.
You have to use three decimal places.
Hope that explains how to figure.