130425-0728 EDT
Suppose you wanted to use a Simpson 260 to measure a small DC component added to a 120 V RMS sine wave.
The Simpson has a DC meter movement with a long enough mechanical time constant that it will not follow a 60 Hz signal. It will just read a steady 0 if there is no DC component. On the 250 V DC range the input impedance is 20,000*250 = 5 megohms. Essentially there will be no more power dissipated in the series resistor and meter movement with 120 V 60 Hz applied than if 120 V DC was applied, 0.003 W. At 250 V the power is 0.013 W.
Theoretically, if you switched to the 2.5 V DC range, and applied the 120 V 60 Hz sine wave with no DC component, then the meter would still read 0 and possibly not even vibrate much. However, the series resistance is 20,000*2.5 = 50,000 ohms. This resistor and the meter movement both might burn up. Power dissipated in 50,000 at 250 V = 62,500/50,000 = 1.25 W.
Add an external 50,000 ohm series resistor, at least a 2W rating, and shunt the meter input with a 30 ufd capacitor. Now the meter becomes a 5 V DC full scale meter when on the 2.5 V range. The AC component at the meter input terminals from a 120 V input will be about 120*90/50,000 = 0.22 V. This will not power overload the meter, and easily is averaged out by the meter movement. DC voltage components from 0 to 5 V can be read.
Other voltage ranges with the external series resistance fixed at 50,000 ohms will not have the 2 to 1 scaling factor.
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