demand load

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bluejean

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what is the demand load at a home with 15kw oven that operates on 249v? and what size tw conductor should be used? please show all calculations.
 
That is not how this works. Show us your attempt to answer the question, and we can show you where you make a mistake, if you do.

Can you describe for us in more detail why a Verizon Tech / Hobbyist would need to know this information in the execution of their professional duties? This forum is not intended for do-it-yourself, as stated in the forum rules.
 
This is a home work assignment in a course i'm taking. 15,000 x 55% =9750w. What about over 12kw increase 5% for each kilowatt. Is there more then one way of doing this?
 
No, you're on the right track.

Note 1 states that for a range over 12kW, then you add 5% to the demand value given in Column C.

So, Column C states that for one range, you multiply the nameplate value times (8*1.15) to reach your demand load for one range. So that would make your answer _________.

Thanks for the explanation about your background. You might want to change your "relation to the industry" to "student" to avoid interrogation in the future. Welcome to the forum.
 
I'm slow on this. So that's 9.2, then what do I do. Or is that it. What about the size tw copper conductor should be used?
 
15KW is 3 KW greater than 12KW. So you need to increase the table load by 3*5 percentage points. So you need to increase 15% above the table value (same as multiplying by 1.15) of 8KW for a this range as the previous posters mentioned. This comes to 9200 watts.

Divide the 9200 watts by the applied voltage (240) to get amps (volts * amps = watts for this problem).

Look up the wire ampacities in table 310.16 to see what size you need for the amps you just calculated.

Do you know the temperature limit for TW wire? You'll need to know that in order to use the correct column of table 310.16. If not, look further back in table 310.13 to find its temperature limit.
 
I have another question I'm suck on. A commercial kitchen has three 3kw ovens, a 20kw water heater, and a 3kw deep fryer. what is the demand load for this. Do I calculate everything except the water heater, which I calculate later, or do I calculate all of this together?
 
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