W Wireit Member Dec 3, 2007 #1 I have a demand meter that is reading data in watts and power factor. In order to get the VA would I devide the PF into the watts?
I have a demand meter that is reading data in watts and power factor. In order to get the VA would I devide the PF into the watts?
kingpb Senior Member Location SE USA as far as you can go Occupation Engineer, Registered Dec 3, 2007 #2 KVA = Watts/pf
R rattus Senior Member Dec 3, 2007 #3 Whoops! Whoops! kingpb said: KVA = Watts/pf Click to expand... King, you are off by a factor of 1000! Pa (VA) = Pr (watts)/PF Pa (KVA) = Pr (KW)/PF PF must be expressed as a decimal fraction. Watch those kilos!
Whoops! Whoops! kingpb said: KVA = Watts/pf Click to expand... King, you are off by a factor of 1000! Pa (VA) = Pr (watts)/PF Pa (KVA) = Pr (KW)/PF PF must be expressed as a decimal fraction. Watch those kilos!
kingpb Senior Member Location SE USA as far as you can go Occupation Engineer, Registered Dec 4, 2007 #4 Ahh, yep! I second that..... 220, 221, whatever it takes!