Can you show us your work and how you figured it, and maybe we can direct you from there?

I'm on mobile so I'll do my best

2,500 ft² x 3VA/ft² = 7500VA. Per 220.12

10,000 VA fixed space heater @ 100%. Per 220.51

11,000 VA range turns to 8 kW per table 220.55

Also to mention kVA shall be considered equivalent to kW in 220.55

So...8000VA?

4,500 VA clothes dryer turns to 5000 VA. Per 220.54

The 2 non-motor appliances at 2,500 VA

800 VA x 1.25 = 1,000 VA per 220.50 which took me to 430.24 (1)

7,500 general Lighting Loads

10,000 fixed space heater

8,000 range

5,000 clothes dryer

1,000 disposal motor

2,500 non-motor appliances

3,000 (1,500 x 2) per 220.52 (a)

1,500 per 220.52 (b)

Using the example in Annex D...

7,500 + 3,000 ( 220.52 (a)) + 1,500 ( 220.52 (b)) + 10,000 + 1,000 + 2,500

= 25,500

3,000 VA @ 100% per table 220.42

25,500 VA - 3,000 VA = 22,500 @ 35% = 7,875

7,875 + 8,000 + 5,000 = 20,875 VA

20,875 is not what I'm supposed to get.... it's supposed to be 32,650 VA.