Let's try this:
If a feeder is only serving the lighting load, in a dwelling unit that's 3VA per sqft before any load calculation, so if you are dealing with 2500sqft you have gross 7500VA. 220.42 now applies. 1st 3000VA at 100% 3000/240 is 12.5A, leaving 4500VA at a factor of 35% leaving 1575VA/240V is 6.56A so the load is 19.06A. If none of that load is continuous then for 215.2(A)(1)(a) you use only 100% or 19.06A. Lighting in a commercial space could fit the definition of a continuous load and then would be calculated at 125%, or 23.825A for 215.2(A)(1)(a).
Now for 215.2(A)(1)(b) you apply adjustment and correction factors to the table ampacities to determine the conductor size, but only at 100% of the load, even if the load is continuous. If an adjustment needs to be made per 310 for temp 310.15(B)(2)(a) 75° column, ambient temp 87-95° of 0.94, you need a conductor whose table ampacity is 19.06/0.94 = 20.28A to end up with an ampacity of 19.06A.
So if this 19.06A load is a continuous load, (a) controls and you will need a conductor with a table ampacity of 23.83A. While if this 19.06A load is a non-continuous load, then (b) controls and you will need a conductor with a table ampacity of 20.28A.
Cheers, Wayne