j_braddock
Member
i do not understand one of the examples i am working with in regards to feeder sizing & protection.
any help would be greatly appreciated.
230 volt system, single phase, inverse time breaker for feeder.
the system invloves two motors 5 hp & 3 hp.
1. the motor full load currents are 28 for 5 hp & 17 for 3 hp. table 430.148
2. the branch circuit protection is 28 * 2.5 = 70 amps for the 5 hp & 17 * 2.5 = 42.5 (next size up) = 45 amps. based on 430.52(c)1, table 430.52, and 240.6(a).
3. feeder conductor is 28 * 1.25 + 17 = 52 amps. table 310.16 allows for a #6 rated 55 amps at 60 deg c.
4. feeder protection - 70 amps + 17 amps = 87 amps (next size down) = 80 amps. based on 430.62
here is my questions
#1 why is the feeder conductor based on 60 deg c rather than 75 deg c?
#2 why do you size down the feeder protection rather than going to the next size up?
thanks in advance,
j_braddock
[ March 12, 2004, 02:19 PM: Message edited by: j_braddock ]
any help would be greatly appreciated.
230 volt system, single phase, inverse time breaker for feeder.
the system invloves two motors 5 hp & 3 hp.
1. the motor full load currents are 28 for 5 hp & 17 for 3 hp. table 430.148
2. the branch circuit protection is 28 * 2.5 = 70 amps for the 5 hp & 17 * 2.5 = 42.5 (next size up) = 45 amps. based on 430.52(c)1, table 430.52, and 240.6(a).
3. feeder conductor is 28 * 1.25 + 17 = 52 amps. table 310.16 allows for a #6 rated 55 amps at 60 deg c.
4. feeder protection - 70 amps + 17 amps = 87 amps (next size down) = 80 amps. based on 430.62
here is my questions
#1 why is the feeder conductor based on 60 deg c rather than 75 deg c?
#2 why do you size down the feeder protection rather than going to the next size up?
thanks in advance,
j_braddock
[ March 12, 2004, 02:19 PM: Message edited by: j_braddock ]