I am fairly new to fire alarms and have an issue with a verification of bell circuits. I have 2 bells on a signal circuit (class b with EOL resistor), I can create an open and a ground on 2 wires, but on the other two I get the open but no ground on 1 wire, and an open and when I try to get a ground, it clears the circuit and the panel is clear? What is going on?
I'm not entirely sure what your getting at, let me try:
Is the line side the 2 wires you get an open and a ground fault (that's normal)
Then the load side must be the other. If so, when the load side is not connected to the line side(connected to the panel) you will not see a ground fault. There is no path from the bell circuit terminal to ground, assuming both legs of the load side are lifted from the line.
A ground fault on only one side could indicate a t-tap, diode present, 2nd ground fault location, miswire etc..... If it is not connected to the line side conductors
If the panel goes normal when you ground a conductor, there is a 2nd ground fault, that is on the same conductor, it is completing the circuit to the eolr, as to why a ground fault is not indicated makes me think I didn't understand fully. Unless thehigh resistance ground fault is above the panel's detection threshold, but sees the resistor-which is odd.
I don't recommend intentionally grounding circuits as a test method, you could kill the panel. If there were more than one faulted circuit, you could induce current through the panel from a foreign source, among other possible issues.