Re: generator sizing
Your formula is backwards, at best. Sometimes, KVA = (120%) of KW, but it is physically impossible for it to be the other way around.
I can't draw pictures and post them. So I'll describe something, and you draw it on paper.
Draw a short horizontal line segment. At the right end point, draw a short vertical line segment. Connect the left end point of the horizontal line segment with the upper end point of the vertical line segment. You have drawn a right triangle, and the right angle should be on the right side of the figure.
Label the horizontal line segment "KW," the vertical line segment "KVAR," and the hypotenuse "KVA." Label the angle at the left edge of the figure "theta."
"Theta" is the phase angle by which the voltage leads the current (in an inductive circuit, which we see more often than a capacitive circuit). The cosine of theta is the "power factor" of the circuit.
To get KW, if you know KVA, you multiply KVA times the power factor. But this necessarily means that just knowing KVA is not enough. You need two facts (i.e., lengths of sides or measures of angles) about any right triangle, in order to calculate the remaining facts. KVA is just one side (the hypotenuse), one fact. You need one more.
Please note that a power factor of 83.3% will give you the expression that I put at the top of this post: If pf = .833, then KVA = (120%) of KW.
Please note also that KVA, being the hypotenuse of the triangle, can never be shorter than either of the two sides. That is why the expression you gave is impossible.
