Your second picture (
20200825_121849.jpg) shows the waveform of I
a going between a positive peak value of about +11A and a negative peak value of about -48V. The waveform is reasonably symmetrical in the positive and negative directions, and so the average value of the waveform over one cycle (and over the long term) is about (11A - 48A) / 2 = -19A. This is the DC component of the waveform. A waveform that only has an AC component and no DC component will average to zero.
Your last picture (
20200825_121701.jpg) shows the waveforms of both I
a and I
b in the same plot. You can see that once again the average of I
a is about -19A DC.
Now maybe a -19A DC offset has been applied only to the channel with the I
a waveform by using an adjustment within the analyzer itself, but I think that's unlikely (and maybe not even possible).