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zappy:
don_resqcapt19 gave a very good description.
To help you understand this:
The EGC (equipment grounding conductor - ground pin in the outlet) when correctly wired is connected to the neutral only at at the service entrance. Under normal conditions there is no load current in this EGC. There may be some small currents from electronic filters, but these currents are not normally large compared to the EGC wire size. Thus, from the connection of the EGC at the service entrance to any point on the EGC there should be virtually zero voltage drop.
This means that at any point on any EGC you have the equivalent of a long meter probe going back to the neutral at the service entrance. Or the equivalent of getting a wire, connecting it to the neutral at the service entrance, and running this external wire to one terminal of your meter wherever the meter is.
Therefore the the voltage read between the outlet ground pin and the neutral pin is the voltage drop scross the neutral conductor from the service entrance to the point of measurement.
Suppose you have a 100 ft length of #12 neutral wire with 20 A load current thru the neutral. The resistance of 100 ft of #12 copper wire is 0.16 ohms. The voltage drop is 20*0.16 = 3.2 V. Half that length is 1.6 V, or half the current at 100 ft is 1.6 V.
Use basic electricaal theory and you can answer many of these questions yourself.
If by accident or error there is a connection of the EGC and the neutral at some point in the circuit away from the service entrance, then the voltage reading would likely be less than calculated.
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