Induction Range

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Grouch1980

Grouch1980

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New York, NY
Hi all,
If you look at the attachment, it's an induction range cutsheet. It's a combo oven with 4 heating 'elements' on the top. If you look at the cutsheet, you'll see the power breakdown for each item in the middle column. How does one calculate the total power for this? Also, why would they show 11,700 watts and 14,000 watts on the top right if both of these wattages exceeds the 40 amp circuit breaker rating that this appliance needs? Dividing those numbers by either 208 volts or 240 volts give you amperages that exceed 40 amps.
 

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I get 13,400 when I total the numbers. Also, elements cycle, so they're not considered to be continuous loads.

And that's presuming there's no switch that prevents oven and convection elements running simultaneously.

How often does one need to use all four burners while using the oven? Thanksgiving and Christmas, maybe?
 
yeah, i have no idea how they get their total numbers on the top right. and what doesn't make sense either is that the total numbers exceed 40 amps. And if you call the vendor, they won't even help, either they play dumb or they tell you they can't divulge the information.
 
Range branch circuits are calculated according to Table 220.55 which adds in a demand factor. You would not need to just divide the total range wattage by the voltage.
 
infinity said:
Range branch circuits are calculated according to Table 220.55 which adds in a demand factor. You would not need to just divide the total range wattage by the voltage.
Click to expand...
What would I use for the wattage though in this case? before applying the demand factor in that table.
 
So do electric ranges typically have an internal control to prevent overloading the branch circuit, or could you actually turn everything on high at once?

Also, if the range spec sheet says 40A (presumably based on that demand factor), is that a minimum or a requirement? I.e. if you have existing 14-50 receptacle on a 50 amp breaker, would the range above require you to change it to a 40A breaker?

Cheers, Wayne
 
The dual wattage numbers are due to the 208/240 rating.
The 40 amp would be the minimum acceptable branch circuit. You can certainly supply it with a 50 amp circuit provided you have properly rated conductor.
 
I think i'm more lost now before 😭😭😭 I have no idea how to interpret the cut sheet.

EDIT: What power / KW do I use in a load calculation?
 
Last edited:
augie47 said:
The dual wattage numbers are due to the 208/240 rating.
The 40 amp would be the minimum acceptable branch circuit. You can certainly supply it with a 50 amp circuit provided you have properly rated conductor.
Click to expand...
I wish the cut sheet would say that... that 40 amps is the minimum breaker. then what's the max breaker you can use?
 
Grouch1980 said:
What would I use for the wattage though in this case? before applying the demand factor in that table.
Click to expand...
The wattage is the output so you would use the number that corresponds to the voltage of the system you're connecting it to. If it's 208 volts then the current will be lower and the output will be lower (smaller KW value) than if you connected it to 240 volts. Take a look at T220.55 and see if you can do the calculation.
 
infinity said:
The wattage is the output so you would use the number that corresponds to the voltage of the system you're connecting it to. If it's 208 volts then the current will be lower and the output will be lower (smaller KW value) than if you connected it to 240 volts. Take a look at T220.55 and see if you can do the calculation.
Click to expand...
I'm using a 208 volt system. so i'll use the 11,700 watt value. But dividing this by 208 volts gives you an amperage higher than the 40 amp circuit breaker they recommend. this is where i don't follow.
 
The manufacturer and the Table take into account the fact that the heating elements cycle and the unit will seldom pull over 40 amps and even then for short duration thus the 40 amp breaker.
IMO, if you wanted to wire for a 50 amp circuit there would be no problem.
(One important factor: is this for household use ?? )
 
augie47 said:
The manufacturer and the Table take into account the fact that the heating elements cycle and the unit will seldom pull over 40 amps and even then for short duration thus the 40 amp breaker.
IMO, if you wanted to wire for a 50 amp circuit there would be no problem.
(One important factor: is this for household use ?? )
Click to expand...
yes, this is for household use. any idea on what i should use for the load calculation? just use 40 amps max * 208 volts to get the wattage, and then apply the demand factor from the table?
 
Your actual current would be 11,700/208. The Table is based on wattage. The 11.7kw range has a calculated load of 8 kw and Note 4 allows you to use that for your branch circuit thus 8kw.
Your concern is likely unnecessary. There are countless ranges in that power range operating on 40 amp circuits.
 
208 volts is not generally for dwellings unless it is an apt. style place with 3 phase.

As stated several times the table allows this unit on a 40 amp circuit. In fact, any range from 9kw-16kw can be used on a 40 amp circuit.

All ovens cycle on and off and the chances of having all burners on high and the oven going is not likely. I guess one could trip a 40 amp overcurrent protective device if that happened.
 
yes, it's an apt. building with 208 volts, 3 phase incoming power, and 208 volt, 1 phase feeders to each of the apartments. I think I see what's going on. The 40 amp breaker is already taking into account the demand factor from the table (8kw)... ok i see it now. and my load calc would use 8 kw.

what i don't see is how they got those totals of 11.7 kw and 14 kw. doesn't matter how i add up the elements, i don't get those totals... doesn't matter though for what i need.

Thanks everyone!
 
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