Re: Law of Sines
Extend a vertical line from Line c = 3 to the point where Line a = 1 intersects with Line b = 2.375 , the vertical line perpendicular to Line c.
The vertical line is the "X" ( vertical) value of two rite-triangles that "abut" each other.
"X" = 1 X sinB = 1 X sin45 = 1 X .707 = .707
2.375 X sinA = .707
sinA = .707/2.375 = .3 A = 17'
The "Y" value of the angle A rite-triangle =
3 - (a x cos45) = 3 - ( 1 x .707) = 3 - .707 = 2.293
tanA = "X"/ "Y" = .707/2.293 = .308 A = 17'
angC = 180 - ( 45 + 17 ) = 180 - 62 = 118
