ramsy said:
I would need a reference to see where voltage potential affects motor power factors.
Pick up any text on control of induction motors via adjustable speed drives. The one that I have at hand (not the best for this discussion, but convenient) is Motor Control Electronics Handbook, Richard Valentine, McGraw-Hill. For this discussion, the section on slip optimization of induction motors (8.3.4) is most relevant.
The output of the motor can be called its mechanical operating state, a particular combination of torque and speed. A given mechanical operating state may be produced by a large number of different combinations of voltage and drive frequency. You could use relatively high drive voltage, combined with low slip, or you could use lower drive voltage combined with greater slip, or anything in between. The lowest possible drive voltage for a given mechanical state is set by the break-away torque of the motor at the particular drive voltage and frequency. The highest possible drive voltage is limited by saturation current flow and excessive heating.
As the terminal voltage is increased, the magnetizing current flow increases, the air gap magnetic flux increases, and the 'torque producing' current flow decreases. At low voltage, lots of current has to flow in order to produce torque in the weak magnetic field, and you get standard I^2R heating of the coils. At high voltage, lots of current has to flow to produce the magnetic field, and again you see I^2R heating, in addition to lots of magnetic losses in the iron.
Between these two limit points, there is a particular combination of voltage and frequency which will cause the motor to operate most efficiently. This is the operating point where the sum of all losses in the motor is minimized.
As the voltage goes down from the most efficient operating point, you will have less magnetizing current flow, more torque producing current flow, and power factor will _go up_ even though efficiency is going down.
As the voltage goes up from the most efficient operating point, I would expect magnetizing current flow to go up, but losses are also going up, so I don't know which way power factor would go.
-Jon