midnightprogrammer
Member
I have a double gang box (34 cubic in capacity) with (2) 14/3 and (2) 12/2 separate circuits that will house (2) switches.
The question I have has to do with the wording on 314.16 (B)(4) as to the allowances taken for the Devices in the box. One of the switches will have #14 AWG conductors, the other will have #12 AWG conductors.
I believe this is how the box fill calculation should turn out....
So....
6 #14 @ 2.0 = 12 Cu In
4 #12 @ 2.25 = 9 Cu In
1 Gnd @ 2.25 = 2.25 Cu In
1 Clamp @ 2.25 = 2.25 Cu In
1 Dev @ 2 * 2.0 = 4.00 Cu In (Here's where the question comes in)
1 Dev @ 2 * 2.25 = 4.50 Cu In (Here's where the question comes in)
Totaling 34 Cu In.....
Did I do it right or have I overfilled the box?
Thanks
The question I have has to do with the wording on 314.16 (B)(4) as to the allowances taken for the Devices in the box. One of the switches will have #14 AWG conductors, the other will have #12 AWG conductors.
I believe this is how the box fill calculation should turn out....
So....
6 #14 @ 2.0 = 12 Cu In
4 #12 @ 2.25 = 9 Cu In
1 Gnd @ 2.25 = 2.25 Cu In
1 Clamp @ 2.25 = 2.25 Cu In
1 Dev @ 2 * 2.0 = 4.00 Cu In (Here's where the question comes in)
1 Dev @ 2 * 2.25 = 4.50 Cu In (Here's where the question comes in)
Totaling 34 Cu In.....
Did I do it right or have I overfilled the box?
Thanks