C chan0828 Member Aug 5, 2010 #1 Hi, I have a difficulty of this calculation. In 208V 3ph-4w system, A-N has a coil with an impedance of 8 ohms and a power factor of 0.9 lag C-N has a heater load of 10 ohms Calculate the neutral current. Can anybody help me?
Hi, I have a difficulty of this calculation. In 208V 3ph-4w system, A-N has a coil with an impedance of 8 ohms and a power factor of 0.9 lag C-N has a heater load of 10 ohms Calculate the neutral current. Can anybody help me?
charlie b Moderator Staff member Location Lockport, IL Occupation Semi-Retired Electrical Engineer Aug 5, 2010 #2 We like to help those who help themselves. Can you tell us what you have tried, and what (if any) results or problems you have so far? Welcome to the forum.
We like to help those who help themselves. Can you tell us what you have tried, and what (if any) results or problems you have so far? Welcome to the forum.
C Cold Fusion Senior Member Location way north Aug 5, 2010 #4 chan0828 said: ...In 208V 3ph-4w system, A-N has a coil with an impedance of 8 ohms and a power factor of 0.9 lag C-N has a heater load of 10 ohms Calculate the neutral current. ... Click to expand... Since you are doing this type of problems, I suspect you already know most of this. So here's a start: (Definition: Symbol "<" means "phase angle") It's a vector problem. Ia +Ib + Ic + In = 0 Ic = 0 <0 so, Ia + Ib = -In let Va = 120V <0 and Vb = 120V <120 and Vc = 120V <-120 Za = 8 < (acos(.9)) = 8<25.84 degrees Ia = Va/Za = 15 <-25.84 If the math makes sense to you, you likely have a plan for the rest. If not, then we need to attack this another way. cf
chan0828 said: ...In 208V 3ph-4w system, A-N has a coil with an impedance of 8 ohms and a power factor of 0.9 lag C-N has a heater load of 10 ohms Calculate the neutral current. ... Click to expand... Since you are doing this type of problems, I suspect you already know most of this. So here's a start: (Definition: Symbol "<" means "phase angle") It's a vector problem. Ia +Ib + Ic + In = 0 Ic = 0 <0 so, Ia + Ib = -In let Va = 120V <0 and Vb = 120V <120 and Vc = 120V <-120 Za = 8 < (acos(.9)) = 8<25.84 degrees Ia = Va/Za = 15 <-25.84 If the math makes sense to you, you likely have a plan for the rest. If not, then we need to attack this another way. cf