orion5284
Member
- Location
- Plant City, FL
I was told that in a normal branch circuit (not multiwire/shared neutral), if the neutral at the receptacle/device is removed, the electronic equipment could be fried? To me, it seems that it simply would just open the circuit, and if ground is isolated at the device, current would stop because there is no more potential back to source. My understanding is voltage is a "potential" between two points. Since you are removing one of the points no voltage exists. It's only when you introduce another point, like earth/ground, would it seek back to source (secondary side) and thus have potential. If I were to grab a hot, and I'm completely isolated from anything, including ground, there would be no potential and no current.
So, back to the original question, if no potential (voltage), no current. So how would this damage any equipment? I've taken AC and DC theory, and I thought I understood all of this. But, apparently I don't.
Can anyone help me? I can't let things rest until I understand completely.
So, back to the original question, if no potential (voltage), no current. So how would this damage any equipment? I've taken AC and DC theory, and I thought I understood all of this. But, apparently I don't.
Can anyone help me? I can't let things rest until I understand completely.