Note 2

[resistance]

Can we get more input on the below link. Personally, I believe the wording (highlighted) in note two of T.220.55 seems confusing! Maybe I'm over thinking this, but it says what it says! Maybe someone can bring more light to the topic.

Thanks!

http://forums.mikeholt.com/showthread.php?t=113758

 

[Twoskinsoneman]

I've always found the section workable. Is it that you're not able to work it or are you trying to figure out why it uses those specific numbers?

 

[cpal]

Can we get more input on the below link. Personally, I believe the wording (highlighted) in note two of T.220.55 seems confusing! Maybe I'm over thinking this, but it says what it says! Maybe someone can bring more light to the topic.

Thanks!

http://forums.mikeholt.com/showthread.php?t=113758

what is your concern?
with note 2 you find the sum of the name plate kW using 12k as a minimum devide by the number of ranges and and use col C for the number of ranges and increase that value by 55 per 1000 or major fraction of .

10kW + 15kW + 22kW= 12+15+22 = 49k/3=16.3 k three ranges col C = 14 k increase by 10%

 

[resistance]

what is your concern?
with note 2 you find the sum of the name plate kW using 12k as a minimum devide by the number of ranges and and use col C for the number of ranges and increase that value by 55 per 1000 or major fraction of .

10kW + 15kW + 22kW= 12+15+22 = 49k/3=16.3 k three ranges col C = 14 k increase by 10%

That's what I figured! So I was right initially.

So if:
Ranges--10kw and 9kw then: 12Kw+12kw=24/2=12--no need to increase.

 

[cpal]

That's what I figured! So I was right initially.

So if:
Ranges--10kw and 9kw then: 12Kw+12kw=24/2=12--no need to increase.

This is one of the more difficult tables to deal with if you are working with the notes. In the example you give I would go to Col C and select 11k. in most tests and most applications you are looking for a minimum feeder demand. you can size the feeders larger if you wish.

 

[resistance]

what is your concern?
with note 2 you find the sum of the name plate kW using 12k as a minimum devide by the number of ranges and and use col C for the number of ranges and increase that value by 55 per 1000 or major fraction of .

10kW + 15kW + 22kW= 12+15+22 = 49k/3=16.3 k three ranges col C = 14 k increase by 10%

Wouldn't your increase be .20.

 

[resistance]

This is one of the more difficult tables to deal with if you are working with the notes. In the example you give I would go to Col C and select 11k. in most tests and most applications you are looking for a minimum feeder demand. you can size the feeders larger if you wish.

That's making it too easy

 

[cpal]

Wouldn't your increase be .20.

5% for each 1k above 12k

 

[resistance]

Column C also says: See notes

 

[resistance]

5% for each 1k above 12k

Exactly! Your average was 16.3

Note 2 says: Shall be increased 5% for each kilowatt etc etc by which this average (16.3) value exceeds 12KW

 

[cpal]

Exactly! Your average was 16.3

Note 2 says: Shall be increased 5% for each kilowatt etc etc by which this average (16.3) value exceeds 12KW

exactly like I said you would inc by 20%

thanks for not yelling at me

 

[resistance]

exactly like I said you would inc by 20%

thanks for not yelling at me

:grin::wink:

 

[cpal]

:grin::wink:

how do you get the icon into the message????

 

[resistance]

There should be an icon box to your right. Select your smilie, and it will automatically paste--based on where your cursor is.

If you don't have a smilie box, then you may want to go to your profile page, and see if it's active. <<<Not sure on this one.

 

[resistance]

Ok, go here (smilies):
http://forums.mikeholt.com/faq.php?faq=vb_read_and_post#faq_vb_smilies_explain

 

[resistance]

You also have a smiling face [just to the right] next to your colors [A] select bar.