I'll try, but a plumber probably wouldn't understand, because I am going to start with Ohm's Law. The current you get, in any circuit and in any circumstances, is the voltage supplied by the source divided by the resistance that that source must push current through. When you have a short circuit, it means that the resistance went down to nearly zero, due to a wire, a tool, or some other low-resistance item coming into contact with two hot wires (or a hot wire and the neutral, or some other combination).
But the "total resistance" seen by the source is not, quite, exactly zero. That is because there is resistance within the source itself. So when we talk about "available fault current," we pretend that the thing causing the short circuit has absolutely zero resistance, so that the only resistance in the overall circuit, the only resistance seen by the source, is the resistance of the source itself. Then when we divide the source voltage by that value of resistance, and when we get a high value of current, we will be very confident that the actual value of current that we would ever see during a real fault can never be higher than that value. It is the most that the source can give, because of the limitations of the source itself.
Does that work for you?