Panel schedule add in amps

[infinity]

Okay so their is also other way to do it:

Total AC current is 1010A. (1010/3)*.208*1.732= 121.28A
So then that would work

So after all of that the original calculation (total 1Ø amps*120) is correct?

 

[WA_Sparky]

I personally dislike this panel schedule layout completely. 2 separate columns for phase totals, amps per phase rather than VA or KVA, Amp totals not shown at the bottom, no demand factors shown.

Did anyone catch circuit 29,31? 25A/phase on a 20A breaker.

 

[WA_Sparky]

So after all of that the original calculation (total 1Ø amps*120) is correct?

If you consider that a correct form to present data in...
All of the original phase amps are with respect to 120V...
A=103A+217A=320A @120V
B=69.2A+282.9A=352.1A @120V
C=74.7+263.2A= 337.9A @120V
Total amps = 1010A @120V

KVA = 121.2 KVA
Total Amps connected (@208V 3Ø): 121.2KVA*1000/208/1.732=336.43A
Total Demand Load Amps (@208V 3Ø, assuming they assigned demand factors properly): 79KVA*1000/208/1.732=219.29A

 

[WA_Sparky]

Okay so their is also other way to do it:

Total AC current is 1010A. (1010/3)*.208*1.732= 121.28A
So then that would work

I believe your calculation is a little off. It needs "*3" rather than "/3". It's 1010A @120V.

 

[DrSparks]

I believe your calculation is a little off. It needs "*3" rather than "/3". It's 1010A @120V.

Using the wrong operand makes a calculation decidedly more than "a little off."

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[hhsting]

If you consider that a correct form to present data in...
All of the original phase amps are with respect to 120V...
A=103A+217A=320A @120V
B=69.2A+282.9A=352.1A @120V
C=74.7+263.2A= 337.9A @120V
Total amps = 1010A @120V

KVA = 121.2 KVA
Total Amps connected (@208V 3Ø): 121.2KVA*1000/208/1.732=336.43A
Total Demand Load Amps (@208V 3Ø, assuming they assigned demand factors properly): 79KVA*1000/208/1.732=219.29A

Phase currents dont add in three phase


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