Yep... while using the tan(a/2)×s method, it'd be .7249. So if my kick is 45' and spacing is 1" 3/4 center to center
I did .45 x 1.75 equals .7875 ?
Yep... while using the tan(a/2)×s method, it'd be .7249. So if my kick is 45' and spacing is 1" 3/4 center to center
I did .45 x 1.75 equals .7875 ?
Yep... while using the tan(a/2)×s method, it'd be .7249
Oo so if you had 90,that were on a right angle kicking up of down,
in my situation. I have 9 3/4 conduit on a rack stubbing down into pullbox .
the 90,s have a 45' kick in them to inter pullbox .
The he kick is approximately 30 "
. So if my kick is 45' and spacing is 1" 3/4 center to center
I did .45 x 1.75 equals .7875 ?
The equivalent value using the tangent method would be .7249 which is almost exactly 1/16" less than the simplified method. My pencil lines aren't much thinner than 1/16", so I would say it's pretty close.
Edit:
I didn't see that you already replied to this smart$, thank you for the response and my apologies for restating your answer.