PV plan check

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Ok if you really read that section it only talks about the location of the solar breaker, also if you have a 200 panel + 90 amps of solar + everything else I'm guessing that 90% of the time you are going to exceed the busbar rating. Now if you go with one of the new solar panels with the 225 amp bus and a 150 amp main, the amount of solar you can put in is almost unlimited, to a point of course.
That subsection states, in part, "The sum of the ampere ratings of all overcurrent devices on panelboards, both load and supply devices, excluding the rating of the overcurrent device protecting the busbar, shall not exceed the ampacity of the busbar." The underlined part is the MCB. Load device are load breakers. Supply devices is subjective. I believe there's somewhere that states you can use 125% of inverter output rating(s) for upstream determinations... anyone?
 
That subsection states, in part, "The sum of the ampere ratings of all overcurrent devices on panelboards, both load and supply devices, excluding the rating of the overcurrent device protecting the busbar, shall not exceed the ampacity of the busbar." The underlined part is the MCB. Load device are load breakers. Supply devices is subjective. I believe there's somewhere that states you can use 125% of inverter output rating(s) for upstream determinations... anyone?

The way it's written you use 125% of the inverter nameplate rating for 705.12(D)(2)(3)(b) but the solar breaker rating for 705.12(D)(2)(3)(c). Of course, you can use different sections for different panels in series.
 
705.12(D)(2)(3)(b) says exactly what I said. Where two sources, one utility and the other an inverter, are located at opposite ends of the busbar that contains loads, the sum of 125% of the inverter output circuit current and the rating of the overcurrent device protection the busbar shall not exceed 120% of the ampacity of the busbar.

We only have all in one panels here so the main service panel will always contain loads.

Sorry, I misunderstood. I thought thought there was only one panel, the service panel with 400 bus with a 200 amp main breaker

But I still dispute that that is "exactly" what you said. You left out the "ampacity of the busbar" part :) sorry to nitpick, but that made it seem you were interpreting the rule differently.
 
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Sorry, I misunderstood. I thought thought there was only one panel, the service panel with 400 bus with a 200 amp main breaker

But I still dispute that that is "exactly" what you said. You left out the "ampacity of the busbar" part :) sorry to nitpick, but that made it seem you were interpreting the rule differently.
Oh you can nitpick all you want, I'm married with children. No what I have is a 200 amp panel with a 200 amp bus bar feeding a 400 amp panel.

Or to reexplain it in solar terms, solar array to inverters, inverters to 90 amp solar breaker in a 400 amp panel with a 200 feeder, to a 200 amp main service panel/load center with a 200 amp bus.
 
Cowboy,
Maybe I am missing something. Why don't these folks just add a new meter for the solar?
 
Even if the utility allows it without extra fees and charges, which I doubt, adding another meter is a huge extra expense compared to a load side connection.

Also Cowboy mentioned batteries and if the intention is to island with solar power to when the grid goes down, that ain't gonna work if the power and loads are on separate meters.
 
Oh you can nitpick all you want, I'm married with children. No what I have is a 200 amp panel with a 200 amp bus bar feeding a 400 amp panel.

Or to reexplain it in solar terms, solar array to inverters, inverters to 90 amp solar breaker in a 400 amp panel with a 200 feeder, to a 200 amp main service panel/load center with a 200 amp bus.

(2) Bus or Conductor Ampere Rating. One hundred twentyfive percent of the power source output
circuit current shall be used in ampacity calculations for the following:
(1) Feeders. Where the power source output connection is made to a feeder at a location other than the opposite end of the feeder from the primary source overcurrent device, that portion of the feeder on the load side of the power source output connection shall be protected by one of the
following:
a. The feeder ampacity shall be not less than the sum of the primary source overcurrent device and 125 percent of the power source output circuit current.

200A primary source overcurrent device in 200a panel feeding 400 a panel with 200 amp feeder(250 ser al??? 3/0 cu thhwn? ????) 400 amp panel has 90a PV source(125% of output circuit) Yes?????
would that make the feeder required to be rated @ 290 amps??? Just thinking outside the box in this unusual circumstance.
 
(2) Bus or Conductor Ampere Rating. One hundred twentyfive percent of the power source output
circuit current shall be used in ampacity calculations for the following:
(1) Feeders. Where the power source output connection is made to a feeder at a location other than the opposite end of the feeder from the primary source overcurrent device, that portion of the feeder on the load side of the power source output connection shall be protected by one of the
following:
...

200A primary source overcurrent device in 200a panel feeding 400 a panel with 200 amp feeder(250 ser al??? 3/0 cu thhwn? ????) ...
would that make the feeder required to be rated @ 290 amps???

No it would not make the feeder required to be rated 290A, and I highlighted the reasons why not in the language you quoted. There is no portion of the feeder that is on the load side of the power source output connection.

That's from the 2011 edition. He's under the 2014 NEC I believe and the changes have some significant requirement impact.

Actually he was quoting the 2014 or 2017 NEC.
 
No it would not make the feeder required to be rated 290A, and I highlighted the reasons why not in the language you quoted. There is no portion of the feeder that is on the load side of the power source output connection.

Could you define "opposite end of the feeder"? It seems like the opposite end of the 200 amp utility feeder would be the termination point in the 400 amp panel where the PV is tied to the 400 amp buss.

Doesn't PV send power (load) back to the grid if not used by the structure it serves?? --just playing out the code language here.

I do agree in theory that all PV power would be used prior to utliliy therefore the 200 amp feeder could never have more than the OCPD allows & the max load back to the utility is based upon PV production.

so with your assessment I could have a 200 amp service OCPD main disconnect serving a 400 amp main lug panel buss with a 200 amp feeder that is compliant to have a 200 amp back feed breaker for the output of an interconnected electric power source. 200+(200x1.25)= 450 amps ---450 x .8(inverse of 120%) = 360 amps. per NEC 2017 705.12(B)(2)(3)(b) & (d)


quoting the 2017 NEC.
 
...
Could you define "opposite end of the feeder"? It seems like the opposite end of the 200 amp utility feeder would be the termination point in the 400 amp panel where the PV is tied to the 400 amp buss.

The question is whether the source current comes from the opposite end of the feeder as the utility or not. If it is at the opposite end then the currents can't add together (Kirchoff's law). If they can come from the same direction and go to a load then they are not at the opposite ends.

A connection in a panelboard is at the opposite end of the feeder from the utility feed.
A feeder tap to an inverter is not at the opposite end.
If an inverter output is in a panelboard with subfeed lugs that have no OCPD, that is not at the opposite end; both utility and inverter can feed the feeder in the same direction.

Doesn't PV send power (load) back to the grid if not used by the structure it serves?? --just playing out the code language here.

...

That is somewhat irrelevant. The power goes where the load is. Either the load needs to be completely protected, or the arrangement needs to be such that sources can't add together.
 
"There is no portion of the feeder that is on the load side of the power source output connection." Your quote not mine, which brought up the question "Doesn't PV send power (load) back to the grid if not used by the structure it serves??" so there is relevance -- You did notice I agreed with theory ---- using code language a feeder is not the conductors from utility to service equipment so they are not referencing the utility feed.

No comment on the calculations?
 
...so with your assessment I could have a 200 amp service OCPD main disconnect serving a 400 amp main lug panel buss with a 200 amp feeder that is compliant to have a 200 amp back feed breaker for the output of an interconnected electric power source. 200+(200x1.25)= 450 amps ---450 x .8(inverse of 120%) = 360 amps. per NEC 2017 705.12(B)(2)(3)(b) & (d)

I am struggling a bit to get what you are saying. Current flowing from the PV back to the grid subtracts from (not adds to) the current flowing from the grid.
 
Not sure what we are actually talking about here now, but to try to clear up some things...

I was using 'utility' where the proper code term is 'primary source'. The latter term does not imply any distinction between what side of the service point you are on. Power can come from either the primary source or the interconnected source, or both. But, Kirchoff's law says that current can only flow from one at a time between two nodes. The important thing is that, if a load (or set of loads on a feeder) can draw from both sources through the same node, then overcurrent protection must be arranged so that it protects the load. If the sources are at opposite ends of the feeder then no additional overcurrent protection is required. If they are not, then there needs to be an additional overcurrent device between the load and the source interconnection overcurrent device. (Branch circuits are okay because by definition they have protection at the node where they connect, and sources are not allowed to mix with loads in branch circuits.)
 
Had to look at your profile & understand better -- I do not , have not,will not dispute theory you keep repeating I was asking for code interpretation -- Am I correct to decipher you are not a licensed Electrician but may hold a NABCEP license ----- Have you installed AC wiring legally? You are commenting on NEC installations for AC --
The calculations are derived from a simple service, size of feeder to a panel, -- the capacity of buss in panel terminated in & maximum size of breaker for an interconnected power source as well as feeder conductor size is determined through section 705.12.
Terminology is imperative to discussion & the fusing at the transformer(primary source overcurrent device) & the service lateral (feeder) as you seem to understand it as does not fit into the topic as presented for we would be discussing a supply side connection IMO. We will get no where with a difference of definition.
 
A service lateral is not a feeder, and we're not talking about anything on the utilty's side of the service point. (Yes, terminology is important.)

Here is a very long video but as I recall Mike and his group do a good job of discussing these issues. Check out the 26:20 mark for an illustration of a PV connection 'other than at the opposite end' of a feeder. I figured some diagrams might help. The video has lots of them.

As far as the qualification question, I'm legally qualified in the state of California to do any of the work we've been discussing in this thread. And I've done plenty of it.
 
I am struggling a bit to get what you are saying. Current flowing from the PV back to the grid subtracts from (not adds to) the current flowing from the grid.
Correction....

Current flowing from the PV back to the grid means there is no current flowing from the grid to the local system(s). Current cannot flow in both directions at the same time.
 
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