busman
Senior Member
- Location
- Northern Virginia
- Occupation
- Master Electrician / Electrical Engineer
I'll try to make this short.
Customer has a packaged IR sauna delivered. Directions say NOTHING about the electrical requirements. The unit has a 5-20P plug connected to #12 SJOOW coord. I install a dedicated 20A, 120 volt circuit with 5-20R receptacle. Customer assembles unit and it trips the breaker. I go back and measure amps - 26.8A continuous. I call salesman (unit is made overseas) and he says "just put a 30A breaker on it, we've installed tons of these and they work fine." I ask if the unit is UL listed. He says, "No, its EU listed". I ask why put a 20A plug on a unit that draws 26.8A. He claims a 5-20P is a 30A plug. It just went downhill from there.
The question, do I have the following code references correct and do you see any solution:
1) 210.21(B)(2) prohibits a 20A receptacle on a 30A branch circuit?
2) By table 400.5(A), the SJOOW with 2 current carrying conductors is rated for 25A and cannot be used for the 26.8A load.
The only solution I see is to replace the entire circuit with 30A breaker, #10 wire, 30A recpt, 30A cord and plug. Any other ideas?
As always, I greatly appreciate any input you might have.
Thanks,
Mark
Customer has a packaged IR sauna delivered. Directions say NOTHING about the electrical requirements. The unit has a 5-20P plug connected to #12 SJOOW coord. I install a dedicated 20A, 120 volt circuit with 5-20R receptacle. Customer assembles unit and it trips the breaker. I go back and measure amps - 26.8A continuous. I call salesman (unit is made overseas) and he says "just put a 30A breaker on it, we've installed tons of these and they work fine." I ask if the unit is UL listed. He says, "No, its EU listed". I ask why put a 20A plug on a unit that draws 26.8A. He claims a 5-20P is a 30A plug. It just went downhill from there.
The question, do I have the following code references correct and do you see any solution:
1) 210.21(B)(2) prohibits a 20A receptacle on a 30A branch circuit?
2) By table 400.5(A), the SJOOW with 2 current carrying conductors is rated for 25A and cannot be used for the 26.8A load.
The only solution I see is to replace the entire circuit with 30A breaker, #10 wire, 30A recpt, 30A cord and plug. Any other ideas?
As always, I greatly appreciate any input you might have.
Thanks,
Mark