gar
Senior Member
- Location
- Ann Arbor, Michigan
- Occupation
- EE
090207-0747 EST
emahler:
iwire is pointing you in the correct direction.
Without being very accurate if I pick on 1% voltage drop at 400 V and 4 A this is 4 V and 4 A or 1 ohm loop resistance. Ignoring temperature #8 wire has 0.628 ohms per 1000 ft and 20 deg C. 1300 ft of #8 is 0.82 ohms. This just provides a rough background.
If you scale this to 2.8% voltage drop and 480 V the maximum loop resistance is 1*2.8*480/400 = 3.36 ohms. Now you could consider #14 wire. I really doubt that a greater voltage drop is not acceptable, and therefore I would not bother going to #12 to accommodate the rise in copper resistance from temperature. But these are factors you need to analyze.
Do you really need to limit yourself to 2.8% drop? Is the load steady? Even if the load is not steady with what voltage range can it work?
If the load is steady then use a little higher voltage than 480 at the source end to compensate for the voltage drop. Maybe you can do this even if the load is highly variable if there is no problem with over voltage on the equipment. You might also combine this with a Sola constant voltage transformer at the destination.
Do not just look for some equation to give you an answer. Analyze the problem, the limits, apply logic, and make judgements.
Verify that I did not make a mistake in the calculations above.
If I need a 1 HP motor because of the torque requirement, but my duty cycle is 1%, then what size motor should I use?
.
.
emahler:
iwire is pointing you in the correct direction.
Without being very accurate if I pick on 1% voltage drop at 400 V and 4 A this is 4 V and 4 A or 1 ohm loop resistance. Ignoring temperature #8 wire has 0.628 ohms per 1000 ft and 20 deg C. 1300 ft of #8 is 0.82 ohms. This just provides a rough background.
If you scale this to 2.8% voltage drop and 480 V the maximum loop resistance is 1*2.8*480/400 = 3.36 ohms. Now you could consider #14 wire. I really doubt that a greater voltage drop is not acceptable, and therefore I would not bother going to #12 to accommodate the rise in copper resistance from temperature. But these are factors you need to analyze.
Do you really need to limit yourself to 2.8% drop? Is the load steady? Even if the load is not steady with what voltage range can it work?
If the load is steady then use a little higher voltage than 480 at the source end to compensate for the voltage drop. Maybe you can do this even if the load is highly variable if there is no problem with over voltage on the equipment. You might also combine this with a Sola constant voltage transformer at the destination.
Do not just look for some equation to give you an answer. Analyze the problem, the limits, apply logic, and make judgements.
Verify that I did not make a mistake in the calculations above.
If I need a 1 HP motor because of the torque requirement, but my duty cycle is 1%, then what size motor should I use?
.
.
