Service wire size with 83% rule

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infinity

Moderator
Staff member
Location
New Jersey
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Journeyman Electrician
Can you confirm that you take the size of the overcurrent protection device, and not the load demand calc on a panel to apply the 83% rule. I have an existing 150 amp panel with a 2/0 AL. wire. Appliances were added and the new load demand on the service is 140 amps. So do you apply it to 150 x .83= 124.5 amps or 140 x .83= 116.2 amps. I am trying to identify If I can keep the 150 amp panel with a 2/0 AL. wire or I need to upgrade to 175 amp 3/0 AL wire
There are two things involved, the size of the service required and the size of the conductors. A load calculation tells you the minimum service size. The 83% rule tells you the minimum conductor size for that service.

With a 140 amp calculated load the minimum service size of 150 amps (Table 240.6(A) for standard size OCPD's). Multiply that by 83% and you'll get the minimum conductor size for a 150 amp service.
 

kwired

Electron manager
Location
NE Nebraska
Occupation
EC
Can you confirm that you take the size of the overcurrent protection device, and not the load demand calc on a panel to apply the 83% rule. I have an existing 150 amp panel with a 2/0 AL. wire. Appliances were added and the new load demand on the service is 140 amps. So do you apply it to 150 x .83= 124.5 amps or 140 x .83= 116.2 amps. I am trying to identify If I can keep the 150 amp panel with a 2/0 AL. wire or I need to upgrade to 175 amp 3/0 AL wire
You need at least 140 amps of capacity (presuming you did calculations correctly) you likely not finding a 140 amp breaker so you will be going with minimum of 150 amp breaker. If you do so you can use that 83% factor on 150 amps to select a conductor. Should you decide to go with 175 or 200 amp breaker then you apply that 83% to 175 or 200 when selecting a conductor - whether the calculated load is 140, 45, 125, or 173
 
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