naturalspry
New member
- Location
- Kansas City, MO, USA
In high-voltage electrical substations, one of the requirements that I've heard while working is that shielded control cable should be installed with a parallel conductor the same size as the ground grid conductor in the event of switching surges / faults.
IEEE 80 has a short statement on this phenomenon in section 17.5:
"If the control cable sheath is grounded at widely separated points, large potential gradients in the ground grid during faults may cause excessive sheath currents to flow. One solution is to run a separate conductor in parallel with the control cable connected to the two sheath ground points. The induced current in the separate conductor will induce an opposing voltage on the control cable sheath, thereby minimizing the current in the sheath."
2 quick questions:
1) The language from the standard makes it appear as though the sheath is grounded at both ends, is this an accurate / acceptable practice?
2) How does the 'sacrifice' conductor (for lack of a better term) protect the cables in this case? I'm having trouble understanding this phenomenon in general, but more specifically from an EMF point of view.
Thanks,
naturalspry
IEEE 80 has a short statement on this phenomenon in section 17.5:
"If the control cable sheath is grounded at widely separated points, large potential gradients in the ground grid during faults may cause excessive sheath currents to flow. One solution is to run a separate conductor in parallel with the control cable connected to the two sheath ground points. The induced current in the separate conductor will induce an opposing voltage on the control cable sheath, thereby minimizing the current in the sheath."
2 quick questions:
1) The language from the standard makes it appear as though the sheath is grounded at both ends, is this an accurate / acceptable practice?
2) How does the 'sacrifice' conductor (for lack of a better term) protect the cables in this case? I'm having trouble understanding this phenomenon in general, but more specifically from an EMF point of view.
Thanks,
naturalspry