Math short cuts I have found to make electrical calculations simple.
Short cut #1
I always had a problem dividing long numbers but not multiplying them so I come up
with this.
Example What is the load capacity of a 75 KW single phase transformer at 240 volts?
Conventional way divide----75000 / 240=312 amps.
My way is to multiply by the reciprocal of the voltage in this case is 240 volts.
The reciprocal of 240 is .0041666
Example .0041666 x 75000=312 amps.
You can find the reciprocal of a number by dividing 1 by the number.
Example 1 divide by 120 volts, 1 / 120=.083333
You can make a list of the logarithms of these numbers.
1.-120=.00833
2.-240=.00416
3.-277=.00361
4.-480=.00208
Short cut #2
If an electrical heater dissipates 2000 watts at 208 volts what would this same heater
dissipate at 240 volts. This is assuming the heaters resistance does not increase or
decrease with the extra 32 volts.
Conventional way first find the amperes of the heater. 2000 / 208=9.6 amps.
Next find the resistance in ohms of the heater. 208 / 9.6=21.6 ohms
Next find how many amperes the heater will pull at 240 volts 240/21.66=11.11 amps.
Next and last we can multiply to find watts at 240 volts 11.11 x 240=2666 watts
My way is one step multiply 2000 x 1.333=2666 watts
You can use 1.33313609 with the wattage ratio between 208 and 240 only.
Here is a table of ratios
120 to 130=1.1726 or for practical use 1.17
208 to 240=1.33313609 ? ? ? ? 1.33
240 to 277=1.3321006 ? ? ? ? 1.332
You can also reverse this process by dividing.
Example a 120 volt, 100 watt light bulb dissapates aprox. 85 watts at 130 volt.
100 / 1.17=85 watts or 85.28 watts
Ronald
Short cut #1
I always had a problem dividing long numbers but not multiplying them so I come up
with this.
Example What is the load capacity of a 75 KW single phase transformer at 240 volts?
Conventional way divide----75000 / 240=312 amps.
My way is to multiply by the reciprocal of the voltage in this case is 240 volts.
The reciprocal of 240 is .0041666
Example .0041666 x 75000=312 amps.
You can find the reciprocal of a number by dividing 1 by the number.
Example 1 divide by 120 volts, 1 / 120=.083333
You can make a list of the logarithms of these numbers.
1.-120=.00833
2.-240=.00416
3.-277=.00361
4.-480=.00208
Short cut #2
If an electrical heater dissipates 2000 watts at 208 volts what would this same heater
dissipate at 240 volts. This is assuming the heaters resistance does not increase or
decrease with the extra 32 volts.
Conventional way first find the amperes of the heater. 2000 / 208=9.6 amps.
Next find the resistance in ohms of the heater. 208 / 9.6=21.6 ohms
Next find how many amperes the heater will pull at 240 volts 240/21.66=11.11 amps.
Next and last we can multiply to find watts at 240 volts 11.11 x 240=2666 watts
My way is one step multiply 2000 x 1.333=2666 watts
You can use 1.33313609 with the wattage ratio between 208 and 240 only.
Here is a table of ratios
120 to 130=1.1726 or for practical use 1.17
208 to 240=1.33313609 ? ? ? ? 1.33
240 to 277=1.3321006 ? ? ? ? 1.332
You can also reverse this process by dividing.
Example a 120 volt, 100 watt light bulb dissapates aprox. 85 watts at 130 volt.
100 / 1.17=85 watts or 85.28 watts
Ronald