gadfly56
Senior Member
- Location
- New Jersey
- Occupation
- Professional Engineer, Fire & Life Safety
I don't have access to that document, but a 41' x 10' rectangle doesn't quite fit inside a 42' diameter circle. The diagonal of the rectangle is sqrt(41^2 + 10^2) = 42.2'. A 40' x 10' rectangle fits, however, as does a 41' x 9' rectangle.
Cheers, Wayne
It is an artifact of the 0.7 multiplier for non-prescriptive coverage. It should actually be 0.707. Or really actually sqrt(2)/2 because the multiplier is based on the hypotenuse of the right triangle formed by the detector and the line perpendicular to one side and then extending to the corner. So 15^2 + 15^2 = 2*225 = 550. If we take the square root of that we get 21.213(etc) feet. Then 30/21.213(etc) is 0.707(etc). The wriggle room is that the prescriptive space is allowed to wander per A17.7.3.2.3.1 so it's +/- 5% or +/- 18 inches.