Someone fed a 100 amp subpanel with a 6/3 and an 8/3 copper paralleled. These were protected (or not) by a 100 amp breaker. This is not part of the job I'm there to do, but it may be serious enough to fix regardless. I haven't mentioned it to the homeowner yet. This is a residence. However, it got me wondering. Lets say the load was 60 amps. How would the current be distributed on each wire? 30/30 40/20 60/0 ??? I have no idea and I know it's not right, just wondering.
