Ragin Cajun
Senior Member
- Location
- Upstate S.C.
Now that I have read the posts and gathered what wits I have left, I can look at it a slightly different way.
If there were three single phase loads, the connected KVA would be:
480V*60A =28.8 KVA * 3 = 86.4 KVA TOTAL 3 PHASE LOAD.
Thus, line current is 86.4KVA/[sqrt 3 * 0.480KV] = 103.9A per phase.
The current at "??" would also be 103.9A. The other two legs would be 60A.
Backhanded way to avoid vexing vectors - at least in this case!
Unbalanced 3 phase loads are so much fun. ;-(
Beaucoup thanks for all your help!
RC
If there were three single phase loads, the connected KVA would be:
480V*60A =28.8 KVA * 3 = 86.4 KVA TOTAL 3 PHASE LOAD.
Thus, line current is 86.4KVA/[sqrt 3 * 0.480KV] = 103.9A per phase.
The current at "??" would also be 103.9A. The other two legs would be 60A.
Backhanded way to avoid vexing vectors - at least in this case!
Unbalanced 3 phase loads are so much fun. ;-(
Beaucoup thanks for all your help!
RC