I need to figure wire size for a 5 hp well pump that is 500' from the source of power.
Is this right?
cm= 2*K*I*D/volts dropped
K = 21.2 alum
I = 28 per T430.148
D = 500'
volt dropped = 240 * .003 = 7.2
cm= 2 * 21.2 * 28 * 500 / 7.2
cm = 82444
2 awg = 66360
1/0 = 105600
2 awg and 1/0 are the common sizes here for 3 wire direct burial.
I should choose 1/0 right?
The pump salesman told my customer he could use 12 awg or 10 awg (copper).
Is this right?
cm= 2*K*I*D/volts dropped
K = 21.2 alum
I = 28 per T430.148
D = 500'
volt dropped = 240 * .003 = 7.2
cm= 2 * 21.2 * 28 * 500 / 7.2
cm = 82444
2 awg = 66360
1/0 = 105600
2 awg and 1/0 are the common sizes here for 3 wire direct burial.
I should choose 1/0 right?
The pump salesman told my customer he could use 12 awg or 10 awg (copper).