VFD Application?

[kwired]

so no speed change is required?

normally 2 belts at ~50% load and full speed (each a different material)
or when 1 is removed from service
1 belt at 100% load and full speed (alternating product at twice the density)

seems like a VFD is not required?

with vfd's
under normal conditions you could slow the belt down and load it to 100%
no advantage
again
Power = work/time = weight x distance / time
if time goes up, ie, slower at 1/2 speed
and weight goes up, twice the material
they offset, the P is the same
work does increase but so does the time

time needed to do the same work decreases, right? I'm sure you know this but think it just came out wrong.

The only way it is worth installing the drive is if there is significant enough change of inefficiencies, otherwise the same work is being done.

 

[Ingenieur]

time needed to do the same work decreases, right? I'm sure you know this but think it just came out wrong.

The only way it is worth installing the drive is if there is significant enough change of inefficiencies, otherwise the same work is being done.

if you slow the belt down, time increases

MORE work is being done, more weight (double the load) over the same distance

offsetting, so same power used

 

[Besoeker]

so no speed change is required?

Nor advantageous.