I have been taught that to find the voltage drop you,1.Measure the length going to the outlet and back so 100' to and 100' back = 200'. 2.The amps of the equipment say 16 amps. 3.14awg wire 12.9 ohms. L X I X R divided by 1000 =VD.So 41,280 divided by 1000 =41.28 Then divide 41.28 by 120v. and that gives you the % which is .344%VD Is this right? I know there are other ways to do VD calculations,i just have this way memorized.It hard to teach a old dog new tricks.
