Service is 208Y/120V. I am doing voltage drop calcs and it seems to me that if the equipment specs are listed for 115V, then I have an extra 5V of voltage drop to work with.
For example, I have a fan with the following manufacturer specs:
From Table 430.248, the FLC at 115V is 16A.
The one-way circuit distance from the distribution panel to the fan is 100 ft.
So I plug the following into my voltage drop calculator:
I get a voltage drop of 5.56V (4.63%). But since my service is 120V, I should have 120 - 5.56 = 114.44V actual voltage at the fan. Since the fan is rated at 115V, then my corrected voltage drop is 115 - 114.44 = 0.56V (0.5%).
Are my logic and calculations correct?
For example, I have a fan with the following manufacturer specs:
- 115V
- 1-Phase
- 11.6 FLA
- 1 HP
From Table 430.248, the FLC at 115V is 16A.
The one-way circuit distance from the distribution panel to the fan is 100 ft.
So I plug the following into my voltage drop calculator:
- 100 ft.
- 120V
- 16A Current
- 1 Set of 12AWG conductors
I get a voltage drop of 5.56V (4.63%). But since my service is 120V, I should have 120 - 5.56 = 114.44V actual voltage at the fan. Since the fan is rated at 115V, then my corrected voltage drop is 115 - 114.44 = 0.56V (0.5%).
Are my logic and calculations correct?