Voltage Drop for single phase service

[lpelectric]

To determine voltage drop for a single phase service consisting of a 200 amp service (160amp load) using 2 #4/0 alu (one each per phase) each having .000328 ohms resistance per foot (as per Chapter 9 Table 8) and 1 #2/0 alu neutral having .000523 ohms per foot and having a total circuit distance of 200 feet, how can I adapt the following formula which is for two conductors (phase and neutral)?

VD = 2 X R X I X D

 

[Smart $]

Remove the 2 from the formula and calculate for each conductor. You will have to determine amps for each conductor. Your total voltage drop will be two of the results added together: VD1 + VD2 = VD for 2-pole loads, VD1 + VDn = VD for 1-pole loads on L1, and VD2 + VDn = VD for 1-pole loads on L2.

 

[charlie]

. . . how can I adapt the following formula which is for two conductors (phase and neutral)?

Use the same formula for the two phases and ignore the neutral. :smile:

 

[lpelectric]

Thank You Smart $ and Charlie. :smile:

 

[billsnuff]

Table 8 chapter 9 4/0 AL = .328 ohm/km or .100 ohm/kft, right? :-?

 

[lpelectric]

Table 8 chapter 9 4/0 AL = .328 ohm/km or .100 ohm/kft, right? :-?

You're absolutely right. Thanks for noting that. :smile: