synchro
Senior Member
- Location
- Chicago, IL
- Occupation
- EE
Another possibility is that the neutrals for A and B are connected together (perhaps within your home run box), and so they are both reading 9 amps because these neutral conductors are sharing equal portions of the total A and B current upstream of that connection.
One thing to try would be to put the clamp around both A and B neutral conductors in the panel, and see if you get 9A + 9A = 18A on the meter. If you get 18A, then it's likely that there is a connection between A and B neutrals. That's because the neutral currents on different phases will not add up in-phase, and so you should get a noticeably lower value than 18A if the neutrals are not connected together.
You could turn the breaker off, disconnect the A and B neutrals, and see if you get continuity between them or to equipment ground. Continuity to equipment ground would result in some of the neutral current flowing through the conduit, as was mentioned in previous posts.
If you had resistive LA-N and LB-N loads with their neutrals connected together, and with your A and B line currents above, the combined neutral current should be about 12.8A due to them being 120° apart. However, it could be 18A as mentioned above if the A and B currents have less overlap in time because of nonlinear loads.
One thing to try would be to put the clamp around both A and B neutral conductors in the panel, and see if you get 9A + 9A = 18A on the meter. If you get 18A, then it's likely that there is a connection between A and B neutrals. That's because the neutral currents on different phases will not add up in-phase, and so you should get a noticeably lower value than 18A if the neutrals are not connected together.
You could turn the breaker off, disconnect the A and B neutrals, and see if you get continuity between them or to equipment ground. Continuity to equipment ground would result in some of the neutral current flowing through the conduit, as was mentioned in previous posts.
If you had resistive LA-N and LB-N loads with their neutrals connected together, and with your A and B line currents above, the combined neutral current should be about 12.8A due to them being 120° apart. However, it could be 18A as mentioned above if the A and B currents have less overlap in time because of nonlinear loads.