watts question?

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gar said:
080614-1537 EST

steveng:

Here is another question to ponder.

Consider a DC circuit.
For a fixed source internal resistance what is the resistance of the load for maximum power transfer to the load?
Should you operate at this condition or not, and why?
What kind of system would operate in the maximum power transfer mode, and what kind would not?

.

Hummm as I recall from 35 years ago - that's an EE330 question. I won't give away the ending:wink:

carl
 
Formula:

(applied voltage divided by rated voltage) squared x actual wattage = new wattage

Example:

Applying 240V to a 480V 1000 Watt Element

(240/480) squared x 1000 Watt = 250 Watt

.25 x 1000 Watt = 250 Watt
 
Yes, Steven the power consumed is the rating of equipment.

So 1000 watts will remain 1000 watts and the current will change inversely proportional to voltage.

Md, when you use 230 ohm resistor for 240 volts application then it is no more a 1000 watts system.

A 1000 watt resistive system designed for 240 volts will have 57.69 ohms resistance...

Another analogy would be that if you have two incandescent bulbs ( 40 watts and 60 watts) of same voltage rating say,..240 volts then the 60 watts bulb will have lower resistance.

Cheers.
 
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