crossman
Senior Member
- Location
- Southeast Texas
cadpoint said:In a Sine wave only the positive side of a graph is doing work,
On this note, what I have been taught is that both the positive and negative portions of the sine wave will do work. Here's the reason why:
Take a mostly resistive circuit. Whenever the voltage is positive, the current will also be positive. If we multiply the current by the voltage, we get a positive number, and this extended through time yields positive work accomplished. Now, on the negative half-cycle of voltage, the current flow is also negative. Multiplying this voltage times this current also yields a positive number for power, which when extended through times yields positive work.
Both portions of the sine wave graph will produce positive power, hence positive work. Essentially, it doens't matter which direction the electrons are flowing, they will do an equivalent amount of work in the typical electrical circuit. By typical, I am mean it doesn't contain directional components such as a diode.
Same thing holds true with realistic reactive circuits, except there will be times on the sine wave where we multiply a positive voltage times a negative current, and vice versa. This is because the voltage and current are out of phase. This will still yield an overall positive power, albeit less than simply multiplying RMS voltage by RMS current. This is where the notion of power factor comes from.
In a theoretically perfect reactive circuit, it is possible to have zero work done, because the energy going to the reactor is exactly returned to the source.
I didn't follow some other parts of your post. I couldn't seperate the "code requires it" from "theory says". The fault may lie on my end because I am not an engineer or physicist.