X, R, for utility transformers

Peter John

Member
Location
Kirkland, WA
Occupation
01 Commercial Electrician
Hello, I'm trying to perform fault current calculations for a commercial building in Kirkland, WA. The Utility transformer is a 150KVA, 12.5KV primary, 208V 3 phase secondary system with a 26,900 fault current rating. PSE(the electrical utility) provides the R/X ratio .3 and %Z 1.55 but per my fault current calculation formula I need the individual X & R values.

Any help would be appreciated, thank you!
 

jim dungar

Moderator
Staff member
Location
Wisconsin
Occupation
Retired Electrical Engineer - Power Systems
Hello, I'm trying to perform fault current calculations for a commercial building in Kirkland, WA. The Utility transformer is a 150KVA, 12.5KV primary, 208V 3 phase secondary system with a 26,900 fault current rating. PSE(the electrical utility) provides the R/X ratio .3 and %Z 1.55 but per my fault current calculation formula I need the individual X & R values.

Any help would be appreciated, thank you!
What software are you using? Most packages will accept X/R and %Z. I can't remember the last time I entered actual X and R values.
 

Peter John

Member
Location
Kirkland, WA
Occupation
01 Commercial Electrician
Hi Jim, I'm trying to do the calculations manually as I run a small electrical shop, but if there is a good program you know of to do them I would love more info!

Thanks
 

jim dungar

Moderator
Staff member
Location
Wisconsin
Occupation
Retired Electrical Engineer - Power Systems
Hi Jim, I'm trying to do the calculations manually as I run a small electrical shop, but if there is a good program you know of to do them I would love more info!

Thanks
Have you searched the internet? For example:
 

dkidd

Senior Member
Location
here
Occupation
PE
Θ = Arctan X/R
X = Sin θ * Z
R = Cos θ * Z or X / (X/R)



Transformer R and X
%Z = 5.75 and X/R = 7
Inverse Tangent 7.00 = 81.8699°
X = Sin 81.8699* 5.75 % = 0.9899 * 5.75 % = 5.6919%
R = Cos 81.8699* 5.75 % = 0.1414 * 5.75 % = 0.8131%

 
Hello, I'm trying to perform fault current calculations for a commercial building in Kirkland, WA. The Utility transformer is a 150KVA, 12.5KV primary, 208V 3 phase secondary system with a 26,900 fault current rating. PSE(the electrical utility) provides the R/X ratio .3 and %Z 1.55 but per my fault current calculation formula I need the individual X & R values.

Any help would be appreciated, thank you!
What exactly are you trying to do? If you are given the fault current of 26,900, what more do you need? I have the old mike holt fault current calculator (I think its no longer on his "free stuff" page and hard to find) and it doesnt ask for XR but it gives 29,847 using 90% PF. Whether its 26,900 or 29,847 does that really make any difference?
 

wbdvt

Senior Member
Location
Rutland, VT, USA
Occupation
Electrical Engineer, PE
First off, understand that the fault current you cite is the infinite bus fault current from the 150kVA transformer. This is adequate to use for sizing the SCCR and AIC for equipment but is totally wrong to use for any arc flash calculations.

Not sure what fault current calculations you need but seems like the first equipment downstream from the transformer would need to be sized greater than 27kA and then I would suspect the next level down you could go with 22kA rated equipment but your modeling will tell you for sure.
 
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