You really need the compressor running load amps and the outdoor fan and indoor fan full load amps to calculate what goes in the panel. Using MCA for the panel load will give an inflated panel load if there is more than one A/C or if the A/C compressor is not the largest motor on the panel. There is no way to calculate running load from the MCA and MOCP values.
[FONT=Times New Roman, serif]Voltage[/FONT] | [FONT=Times New Roman, serif]208V 3Ph[/FONT] | [FONT=Times New Roman, serif]SupplyFan FLA[/FONT] | [FONT=Times New Roman, serif]16.7 (amp)[/FONT] |
[FONT=Times New Roman, serif]Frequency[/FONT] | [FONT=Times New Roman, serif]60 (Hz)[/FONT] | [FONT=Times New Roman, serif]CondensingUnit FLA[/FONT] | [FONT=Times New Roman, serif]4.8 (amp)[/FONT] |
[FONT=Times New Roman, serif]System MCA[/FONT] | [FONT=Times New Roman, serif]65.0 (amp)[/FONT] | [FONT=Times New Roman, serif]CondenserFan Power[/FONT] | [FONT=Times New Roman, serif]830 (W)[/FONT] |
[FONT=Times New Roman, serif]System MOCP[/FONT] | [FONT=Times New Roman, serif]80 (amp)[/FONT] | | |
[FONT=Times New Roman, serif]Compressors RLA[/FONT] | [FONT=Times New Roman, serif]38.0 (amp)[/FONT] | | |
[FONT=Times New Roman, serif]Cooling FLA Total[/FONT] | [FONT=Times New Roman, serif]59.5 (amp)[/FONT] | | |
[FONT=Times New Roman, serif]Unit Oper Range-Nom Voltage[/FONT] | [FONT=Times New Roman, serif]+/- 10%[/FONT] | | |
Thanks for info this is what I found on unit can you explain what numbers I would actually use Thanks again
[FONT=Times New Roman, serif]Voltage[/FONT]
[FONT=Times New Roman, serif]208V 3Ph[/FONT]
[FONT=Times New Roman, serif]SupplyFan FLA[/FONT]
[FONT=Times New Roman, serif]16.7 (amp)[/FONT]
[FONT=Times New Roman, serif]Frequency[/FONT]
[FONT=Times New Roman, serif]60 (Hz)[/FONT]
[FONT=Times New Roman, serif]CondensingUnit FLA[/FONT]
[FONT=Times New Roman, serif]4.8 (amp)[/FONT]
[FONT=Times New Roman, serif]System MCA[/FONT]
[FONT=Times New Roman, serif]65.0 (amp)[/FONT]
[FONT=Times New Roman, serif]CondenserFan Power[/FONT]
[FONT=Times New Roman, serif]830 (W)[/FONT]
[FONT=Times New Roman, serif]System MOCP[/FONT]
[FONT=Times New Roman, serif]80 (amp)[/FONT]
[FONT=Times New Roman, serif]Compressors RLA[/FONT]
[FONT=Times New Roman, serif]38.0 (amp)[/FONT]
[FONT=Times New Roman, serif]Cooling FLA Total[/FONT]
[FONT=Times New Roman, serif]59.5 (amp)[/FONT]
[FONT=Times New Roman, serif]Unit Oper Range-Nom Voltage[/FONT]
[FONT=Times New Roman, serif]+/- 10%[/FONT]
Your calc would be (59.5 amps x 208 volts x sqrt(3)) + 830 watts = 22,265.9 VA (round up to 22,266 VA).
Your calc would be (59.5 amps x 208 volts x sqrt(3)) + 830 watts = 22,265.9 VA (round up to 22,266 VA).
Is this because this 59.5 is given for the full load amps of all fans, motors, etc.. running in the cooling unit?
I guess you want want to use this kW (or VA) vaule in a panel schedule because the MCA has an additional factor on it that is not necessary to include in the load calculation of the panel but rather is just for correct sizing of the circuit to the A/C unit?
Yes, the 59.5 amps is the sum of the 38.0 amp compressor, the 16.7 amp supply fan, and the 4.8 amp condenser fan.
So why add 830 watts for the condenser fan if the 4.8A for the fan is included in the 59.5A? Wouldn't 59.5x208x1.732 = 21.436kVA be more accurate?