I used a formula based on the law of cosines for the calculation and came up with the same values...
I1 = (480^2+48^2 - 2*480*48*Cos(120))^-2
I1 = 505.7
I2 = 50.6
I3 = 482.4
I have to admit when I originally looked at gar and your equations I "felt" something was odd. It didn't really dawn on me what the oddity was until now, because previously I was only concerned with the accuracy of the results. Anyway, just so you (and gar) know, the notation
x^-2 is not acceptable for indicating √
x. A number to a minus (-) power indicates the power of the reciprocal. For example:
x^-1 = 1/
x and
x^-2 = (1/
x)?. The square root of a number in power form would be
x^? or
x^.5.
BTW, if current phase angles are referenced to "RA", then your line current phase angles appear to be off by about 30?.
Assuming the load currents to be the following:
RA= 480A @ 0deg
RB= 48A @ -120deg
RC= 4.8A @ -240deg
I come up with the following line current for L1,L2,L3. These currents are assuming unity power factor:
L1 = 506A @ -26deg should be -355?
L2 = 50.6A @ -145deg should be -115?
L3 = 486A @ -210deg should be -180?