- Location
- Windsor, CO NEC: 2017
- Occupation
- Service Manager
According to Table 314.16(B), #12 is to count as 2.25 cubic inches, not 2.5.
The easiest way I've found to figure the box fill in the field is to:
So, suppose I'm working with a 32.0 cubic inch, two gang box. I have:
(2) 14-2 cables
(2) 14-3 cables
(2) switches
The cables contain an EGC.
Counting:
(II II) (III III) (II II) (I)
I have 15 conductors in the box, converting devices/clamps/studs/hickeys into conductors.
15 x 2.0 = 30 cubic inches.
Converting everything into a common unit, in this case conductors, is the easiest format to solve, IMO. Forget that a switch is a switch and treat it as a conductor, and the problem is far easier to solve.
(I don't think I ever had success figuring out the cheat sheet they often stamp into the boxes. I always go by the cubic inch rating stamped on the box, for less brain-strain.)
The easiest way I've found to figure the box fill in the field is to:
- Count the conductors with your fingers.
- Count the devices, raising two fingers for each device.
- If there are grounding conductors present (yes/no), raise another finger.
- If the clamps are internal to the box (yes/no), raise another finger.
- Studs/hickeys, raise another finger.
So, suppose I'm working with a 32.0 cubic inch, two gang box. I have:
(2) 14-2 cables
(2) 14-3 cables
(2) switches
The cables contain an EGC.
Counting:
(II II) (III III) (II II) (I)
I have 15 conductors in the box, converting devices/clamps/studs/hickeys into conductors.
15 x 2.0 = 30 cubic inches.
Converting everything into a common unit, in this case conductors, is the easiest format to solve, IMO. Forget that a switch is a switch and treat it as a conductor, and the problem is far easier to solve.
(I don't think I ever had success figuring out the cheat sheet they often stamp into the boxes. I always go by the cubic inch rating stamped on the box, for less brain-strain.)
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