80913-0909 EDT
An interesting aspect of AC contactors, relays, and solenoids is:
1. The coil and core combination is an electromagnetic circuit. Much like an electrical circuit.
2. A magnetic circuit has an electrical impedance to AC that is function of flux coupling to the coil of the electromagnetic circuit.
3. A simple solenoid consists of a coil and ferromagnetic movable plunger and fixed parts.
4. A closed magnetic circuit (no air gap) produces the highest AC impedance. As the air gap is increased the AC impedance goes down. Because as the air gap increases there is less flux coupling to the coil.
When a solenoid or relay is de-energized a spring, gravity, or some mechanical force is used to open the magnetic path. Thus, a lower AC impedance and higher current when voltage is applied to the coil.
Energizing the coil produces a current that creates magnetic force that closes the air gap (moving the plunger or armature), now the AC impedance increases, and current drops to a lower level.
The relay or solenoid designed for continuous energization will have a steady state current that won't overheat the coil. If the plunger or armature of this same device does not move from its open or near open position, then because of much higher current the coil will burn out.
If applied voltage and thus current is too low (this current can still be much higher than the current for a fully sealed in device), then the produced magnetic force is not high enough to close the gap, and coil burn out can occur. Very common in AC solenoid valves where the valve gets mechanically stuck. DC solenoids don't have this problem because there is no change in impedance at DC.
If supply voltage was way low, a nominal 120 being less than possibly 90, then I might expect relays or contactors to not close and thus burn out.
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