What is contact interruption distance, and why do dc loads require more?It's set up for use with DC loads.
What is this?
This is an out of the box 1Ø, 480 volt, 200 amp fused disconnect. Any idea what the #1/0 jumper is for?forums.mikeholt.com
Because there is no zero crossing to help extinguish the arc.What is contact interruption distance, and why do dc loads require more?
Zero crossing?Because there is no zero crossing to help extinguish the arc.
An AC voltage rises and falls to zero then goes negative and back to zero as it cycles. Because it goes to zero, arcs are harder to maintain with AC.Zero crossing?
The distance an arc can jump is dependent on the voltage, so the faster the switch opens to a greater distance, the quicker the arc is extinguished.So since that is the case how does increased distance help stop the arc
Maybe someone can explain why it changes something but with that configuration the arc is going across 3 poles instead of just 2.So since that is the case how does increased distance help stop the arc
I see thank you. I’ve not done any higher voltage DC loads. Do you break both the positive and negative leads via the disconnect? Or just the positive?The distance an arc can jump is dependent on the voltage, so the faster the switch opens to a greater distance, the quicker the arc is extinguished.
Breaking both conductors is the equivalent of having twice the distance of just breaking one pole. Or you could break just one but through multiple poles in series. The effect is the same.I see thank you. I’ve not done any higher voltage DC loads. Do you break both the positive and negative leads via the disconnect? Or just the positive?
gotcha makes sense. Thank you sir!Breaking both conductors is the equivalent of having twice the distance of just breaking one pole. Or you could break just one but through multiple poles in series. The effect is the same.