I just address this one:

Saying ?24,000 watts per phase, for a total of 72,000 watts,? is valid. But saying ?200 amps per phase, for a total of 600 amps,? is not valid. That is because, in the context used herein, a ?watt? is a ?watt? is a ?watt,? but an ?amp? is not an ?amp,? nor is it an ?amp.? That, speaking mathematically, is the difference.

What I mean is that if one phase is using energy at a given rate (i.e., the watts expended in that phase), and if another phase is using energy at a given rate, then the total rate of using energy can be found by adding watts to watts, with the answer being expressed in watts. There is no difference between a watt being expended in one phase and a watt being expended in another phase. That is not true with amps.

When we use the word ?amp,? we are not giving a complete physical or mathematical description. To be complete, we need to say that,

(1) In Phase A, we are measuring a current of ?200 amps at a relative phase angle of 0 degrees,?

(2) In Phase B, we are measuring a current of ?200 amps at a relative phase angle of 240 degrees,? and

(3) In Phase C, we are measuring a current of ?200 amps at a relative phase angle of 120 degrees,? so that,

(4) The total amps is given by 200 (angle 0) plus 200 (angle 240) plus 200 (angle 120), with that total being equal to zero amps.

Consider a three phase heater (so that we don?t have to talk about power factor). The watts used in the Phase A element are transmitted into the air, and vanish from the electrical component forever. So too do the watts used in the Phase B element, and so too do the watts in the Phase C element. In that sense, it is easy to see that the total watts used in the three phases will be equal to the sum of the watts used in each of the three elements.

However, the current that leaves the source via Phase A does not disappear from the electrical system. Rather, some of it returns to the source via Phase B, and the rest returns to the source via Phase C. The 200 amps you measure in Phase A is not __in addition to__ the amps you measure in the other two phases. Rather, the amps you measure in Phase A __will become__ the amps you measure in the other two phases. You don?t add them because they are __the same amps.__

It is like saying that you can take a dollar bill out of your left pocket with your left hand, transfer it to your right hand, and place it into your right pocket, and by doing so you now have a ?total of 2 dollars.? And why not? After all, your left hand was moving a dollar, and your right hand was moving a dollar, so weren?t you moving a total of two dollars? I could wish that getting rich would be so easy, but in the end you still have only one dollar, whichever pocket it resides within.