wwhitney
Senior Member
- Location
- Berkeley, CA
- Occupation
- Retired
The 127A on the lines with 3 chargers comes from 48*sqrt(3) A in phase plus another 48A 30 degrees out of phase. The latter out of phase load can be resolved as 48 * cos30 = 41.57A in phase and 48 * cos30 = 24A at 90 degrees out of phase, for a total of 124.7A in phase and 24A out of phase.
The allowable total line current is 50 kVA / 120V / 3 = 138.9A. If we add in phase current, the out of phase component remains fixed, so the allowable in phase component is sqrt(138.9^2 - 24^2) = 136.8. Given the 124.7A in phase, the headroom is the difference of 12.1A.
So sharpening was not useful in this case. : - )
Cheers, Wayne
The allowable total line current is 50 kVA / 120V / 3 = 138.9A. If we add in phase current, the out of phase component remains fixed, so the allowable in phase component is sqrt(138.9^2 - 24^2) = 136.8. Given the 124.7A in phase, the headroom is the difference of 12.1A.
So sharpening was not useful in this case. : - )
Cheers, Wayne