exam question

[97catintenn]

A store front has two show windows each 15' long. What is the minimum amount of receptacles permitted?

 

[jumper]

4 receptacles, 2 per window

210.62 Show Windows. At least one receptacle outlet
shall be installed within 450 mm (18 in.) of the top of a
show window for each 3.7 linear m (12 linear ft) or major
fraction thereof of show window area measured horizontally
at its maximum width.

Also note

220.14(G) Show Windows. Show windows shall be calculated in
accordance with either of the following:
(1) The unit load per outlet as required in other provisions
of this section
(2) At 200 volt-amperes per 300 mm (1 ft) of show window

 

[Little Bill]

4 receptacles, 2 per window

210.62 Show Windows. At least one receptacle outlet
shall be installed within 450 mm (18 in.) of the top of a
show window for each 3.7 linear m (12 linear ft) or major
fraction thereof of show window area measured horizontally
at its maximum width.

Wouldn't that just require 1 per window since the windows are 15' long and the requirements are 12' or major fraction therof? 15-12=3', 6'+ would be major fraction of 12'

 

[jumper]

Wouldn't that just require 1 per window since the windows are 15' long and the requirements are 12' or major fraction therof? 15-12=3', 6'+ would be major fraction of 12'

I thought it would mean the major fraction of a foot.

 

[Little Bill]

I thought it would mean the major fraction of a foot.

Since 12 linear feet is the requirement, I think they mean major fraction of 12'.
That is also what the handbook shows.

 

[Smart $]

A store front has two show windows each 15' long. What is the minimum amount of receptacles permitted?

Do not know whether you worded that verbatim, but it should be minimum number of receptacles required, not permitted.

 

[Smart $]

Wouldn't that just require 1 per window since the windows are 15' long and the requirements are 12' or major fraction therof? 15-12=3', 6'+ would be major fraction of 12'

I thought it would mean the major fraction of a foot.

Since 12 linear feet is the requirement, I think they mean major fraction of 12'.
That is also what the handbook shows.

I agree. One per window. 15 ? 12 = 1-1/4. The fractional part has to be greater than 1/2 for another to be required.

 

[jumper]

Wouldn't that just require 1 per window since the windows are 15' long and the requirements are 12' or major fraction therof? 15-12=3', 6'+ would be major fraction of 12'

Well, crapola.... I blew that one.:ashamed1:

 

[97catintenn]

I started out thinking two per window, too. Thanks for clearing it up!

 

[sharonmose]

I got confused but now all doubts are cleared after reading this answer.

 

[Chris13]

Exam Question

Exam Question

Have an exam prep question just couldn't come up with the answer. Would appreciate any help you guys could offer. "When an NM ko plug is used in a metal box how far does it stick into the box" My first instincts sent me to 110.12 (A), but i think that is the opposite situation. Thanks for the help!!

 

[97catintenn]

112.12 (A) and 314.17 are the only places I see knock out mentioned. But it doesn't say NM plug for a metal box. I'm interested in what others say, but I don't see it being a code question.