You can present voltage as a time varying function. A sine wave. Similarly with current.I think VAR(t) is a meaningful concept to help understand the process.
To make a power meter I would think everything is done with time domain calculations.
thanks again
If that's addressed to me, then thank you!PS, I think you did a great job on fixing the spreadsheet:thumbsup:
But V*A = W for both instantaneous computation and where the power factor is 1.0. Just as we express voltage and current as RMS for it to be single-term meaningful for a period of time, we express VA and W as an average. These values are computed over full cycles of voltage. However, how would you compute the values for a period of time which is not a multiple of a full cycle? Say you were actually computing watt-hours to six decimals (being overly pedantic :blinkYou can present voltage as a time varying function. A sine wave. Similarly with current.
But VA is rms voltage times rms current.
Think about what rms actually is.
The square root of the mean of the squares.
That mean is taken over a period of time.
So you can't represent it in the same way as v(t)
I believe that was addressed to me, but I'll thank you for your contribution to this discussion... :happyyes:If that's addressed to me, then thank you!
as I study the spreadsheet and the above graph which inspired me to start this endeavor, I notice in the linked graph, power does go negative.Here are the images as links to the full scale versions.
The first is a picture that I am trying to duplicate somewhat but I cant find the source for it.
http://daugird.com/cantfindsource.png
But I can calculate instantaneous W from instantaneous values of I and V. To get VA I'd first have to calculate RMS values for V and A.But V*A = W for both instantaneous computation and where the power factor is 1.0. Just as we express voltage and current as RMS for it to be single-term meaningful for a period of time, we express VA and W as an average.
Just extend the series on my spreadsheet.However, how would you compute the values for a period of time which is not a multiple of a full cycle?
You could do it that way.Say you were actually computing watt-hours to six decimals (being overly pedantic :blink. Would you not have to consider the instantaneous values through time domain calculation?
The linked graph has some errors...as I study the spreadsheet and the above graph which inspired me to start this endeavor, I notice in the linked graph, power does go negative.
I wonder what the difference is between the current spreadsheet and the graph.
PS I did find the source.
http://cfpub.epa.gov/ncer_abstracts/index.cfm/fuseaction/display.highlight/abstract/6995/report/F
Thanks again everyone.
But if the period of time was infinitesimally short, we would be approaching instantaneous and therefore W ? VA, as V ? v(t) and A ? i(t)But I can calculate instantaneous W from instantaneous values of I and V. To get VA I'd first have to calculate RMS values for V and A.
You could do it that way.Just extend the series on my spreadsheet.
Except that instantaneous VA has no meaningful context.But if the period of time was infinitesimally short, we would be approaching instantaneous and therefore W ? VA, as V ? v(t) and A ? i(t)
Meaningful is relative to the one doing the perceiving.Except that instantaneous VA has no meaningful context.
You rate a transformer in VA, kVA, or MVA.
RMS Volts times RMS Amps.
The "M" meaning mean precludes instantaneous values.
I think your second point answers your first.Meaningful is relative to the one doing the perceiving.
Yes "M" precludes instantaneous, and that's why I said infinitesimally short period of time.![]()