Normally, the impedance to neutral shown in your diagram is very low compared to the load impedance. The loads in this case are not a voltage divider; the same current does not go through each load. Each load is across 1/2 of the secondary winding.realolman said:It took me a while to get this post accomplished... crossman, I don't understand your second hypothesis. Why would one phase be subtantially higher than the other with respect to the neutral bar.
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The connected lods acting as voltage dividers would do that according to their impedances, but I dont see the high impedance (bad / no connection ) of the neutral doing it.
If the neutral is open (impedance very high), then the loads will act as a voltage divider because the same current goes through both loads. A heavy load (low impedance) on one leg will have a low voltage drop and a light load (high impedance) on the other leg will have a high voltage drop from the same current going through both loads.
